-3x^2+9000x=0

Solution for -3x^2+9000x=0 equation:

-3x^2+9000x=0

a = -3; b = 9000; c = 0;
Δ = b2-4ac
Δ = 90002-4·(-3)·0
Δ = 81000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81000000}=9000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9000)-9000}{2*-3}=\frac{-18000}{-6}
=+3000
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9000)+9000}{2*-3}=\frac{0}{-6}
=0
$